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Exam Code: C2090-421
Exam Name: InfoSphere DataStage v8.5
Updated: Sep 06, 2026
Q & A: 194 Questions and Answers
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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Job Design and Development | 30% | - Data linking and partitioning - Stage usage and configuration - Sequential and parallel job creation - Parameter sets and environment variables |
| Topic 2: DataStage Architecture and Components | 20% | - InfoSphere Information Server architecture - Parallel framework concepts - Project and repository management - Client and server components |
| Topic 3: Data Transformation and Processing | 25% | - Transformer stage logic - Slowly Changing Dimensions (SCD) - Handling NULL values and data types - Lookup and reference data |
| Topic 4: Advanced Features and Integration | 10% | - Job sequences and control flow - Source control integration - Metadata management |
| Topic 5: Job Execution, Monitoring and Troubleshooting | 15% | - Debugging and validation - Performance optimization - Director client usage - Job logs and error handling |
Question 1
Your job uses the MQ connector stage to read messages from an MQ queue. The job should retrieve the message ID into the MessageID field and parse the payload into two fields: Name is to get the first ten characters, Description is to get the remaining characters.
What will accomplish this?
A. First column is MessageID; select the WSMQ.MSGID data element for the Message ID field; second column is Name; select WSMG.MSPAYLOAD data element; third column is Description; select WSMG.MSPAYLOAD data element.
B. First column is MessageID as Binary 24; second column is Name as Binary 10; select WSMG. MSPAYLOAD data element; third column is Description as VarBinary 200; select WSMG.MSPAYLOAD data element.
C. First column is MessageID; select the WSMQ.MSGID data element for the Message ID field; column is Description as VarBinary 200; third column is Name as Binary 10.
D. First column is MessageID; select the WSMQ.MSGID data element for the Message ID field; second column is Name as Binary 10; third column is Description as VarBinary 200.
Question 2
External data conversions fall in two major types - automatic and manual. What are the three automatic conversions? (Select three)
A. Modify operator
B. Sequential File stage
C. Flat Text files
D. Relational data
E. SAS data
Question 3
Which Oracle Enterprise stage read property can be set using -dboptions to tune job performance?
A. arraysize
B. memsize
C. transactsize
D. partitionsize
Question 4
Which two steps are required to change from a normal lookup to a sparse lookup in an ODBC Enterprise stage? (Choose two.)
A. Sort the data on the reference link.
B. Establish a relationship between the key field column in the source stage with the database table field.
C. Change the lookup option in the stage properties to "Sparse".
D. Replace columns at the beginning of a SELECT statement with a wildcard asterisk (*).
Question 5
Which statement is true about buffering?
A. The "buffer" scratch disk pool needs to be defined to allow the framework to perform data buffering.
B. The framework uses /tmp by default for buffering on Unix systems.
C. In a clustered environment, using a disk space on an NFS mount for buffering improves performance.
D. The buffer operator uses both memory and disk storage.
Solutions:
| Question 1 Answer: B,C | Question 2 Answer: C,D,E | Question 3 Answer: A | Question 4 Answer: B,C | Question 5 Answer: D |
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